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Pump Power Calculator (Shaft Power and Motor Sizing)

Enter the flow rate, head, density and pump efficiency to get hydraulic power, shaft power, the minimum motor rating with the API 610 margin and a suggested standard motor size. Defaults come from an ISO 9906 centrifugal pump benchmark.

Inputs

Units
Total pump head (static head plus line losses)
%
Empty = API 610: 1.25 up to 22 kW, 1.15 for 22–55 kW, 1.10 above 55 kW

Results

Shaft power P20.52 kW
Hydraulic power Pᵤ
16.01 kW
Sizing factor K
1.25
Minimum motor rating K·P
25.65 kW
Suggested motor size
30 kW
Save to project / export report

Create a free account and these inputs open as a new project in the workspace, where you can save, edit and export a Word / PDF calculation report.

Results are for reference; check them against the applicable engineering codes. Everything is calculated in your browser and your inputs are not uploaded.

Formula and basis

  • Hydraulic power Pᵤ = ρ · g · Q · H
  • Shaft power P = Pᵤ / η
  • Minimum motor rating = K · P (K per API 610)
  • g = 9.80665 m/s² (standard gravity)

Standards and sources

  • ISO 9906:2012 / GB/T 3216-2016 §3.2: pump power output Pᵤ = ρgQH, pump efficiency η = Pᵤ/P; total head H = Δz + Δp/(ρg) + Δ(v²)/(2g)
  • API 610 (12th ed.) motor power ratings: motor nameplate at least 125 % (≤ 22 kW), 115 % (22–55 kW) or 110 % (> 55 kW) of the rated pump power
  • Suggested motor size is the next common low-voltage motor rating (IEC 60072-1 / GB/T 4772.1 series), for reference only

Worked example (industry benchmark)

180 m³/h clean-water centrifugal pump (ISO 9906 acceptance test calculation)

Inputs: Q = 180 m³/h, outlet minus inlet pressure 3.0 bar, inlet / outlet bore 150 / 100 mm, gauge elevation difference 0.4 m, ρ = 998.2 kg/m³, η = 78 %

Total head H (from pressure, velocity and elevation differences)32.7 m
Hydraulic power Pᵤ16.01 kW
Shaft power P20.52 kW
Sizing factor K1.25
Minimum motor rating K·P25.65 kW
Suggested motor size30 kW

The example matches industry benchmark GC-IND-PUMP-001 in our repository (expected values derived independently with 50-digit decimals and checked by automated tests).

FAQ

What is the difference between shaft power and hydraulic power?

Hydraulic power Pᵤ = ρgQH is the power delivered to the liquid; shaft power P is what the motor delivers to the pump shaft, P = Pᵤ/η. Their ratio is the pump efficiency.

How much motor margin should I allow?

A common rule is API 610: the motor is at least 125 % of rated pump power up to 22 kW, 115 % for 22–55 kW and 110 % above 55 kW. You can also enter your own factor.

How do I get the pump head?

Head = static head (liquid level difference) + pressure difference expressed as head + friction and minor losses in the line. Calculate line losses with the pipe pressure drop calculator and add them.

What if the liquid is not water?

Enter the actual density. For liquids much more viscous than water, pump performance must be corrected (e.g. ISO/TR 17766); this tool does not include viscosity correction.

Can I save the calculation or export a report?

Yes. Click "Save to project / export report" and create a free account; your inputs open as a new project in the workspace, where you can save and export a Word / PDF report.

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